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6x^2-2x/2-5=0
We multiply all the terms by the denominator
6x^2*2-2x-5*2=0
We add all the numbers together, and all the variables
6x^2*2-2x-10=0
Wy multiply elements
12x^2-2x-10=0
a = 12; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·12·(-10)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*12}=\frac{-20}{24} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*12}=\frac{24}{24} =1 $
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